MCQ
Electronegativity of carbon atoms depends upon their state of hybridisation. In which of the following compounds, the carbon marked with asterisk is most electronegative?
  • A
    $ \mathrm{CH}_3-\mathrm{CH}_2-{ }^* \mathrm{CH}_2-\mathrm{CH}_3 $
  • B
    $ \mathrm{CH}_3-{ } ^*\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_3 $
  • $ \mathrm{CH}_3-\mathrm{CH}_2-\mathrm{C} \equiv{ }^* \mathrm{CH} $
  • D
    $ \mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}={ }^* \mathrm{CH}_2$

Answer

Correct option: C.
$ \mathrm{CH}_3-\mathrm{CH}_2-\mathrm{C} \equiv{ }^* \mathrm{CH} $
Electronegativity increases as the state of hybridization changes from $sp^3$ to $sp^2$ and $sp^2$ to sp. Thus, sp hybridized carbon has the highest electronegativity.

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