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Electrostatic potential energy of given system will be
  • A$\frac{{k{Q^2}}}{a} \times 10$
  • B$24\frac{{k{Q^2}}}{a}$
  • C$\frac{{k{Q^2}}}{a}\left( {24 + \frac{{11}}{{\sqrt 2 }}} \right)$
  • D$12\frac{{k{Q^2}}}{a}$
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