MCQ
End product of the given reaction is


- A

- ✓

- C

- D








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$(i)\,Cl\xrightarrow{E.A.}Cl^-\,\,\,\,\,\,(ii)\,C{{l}^{-}}\xrightarrow{I.E.}Cl\,\,\,\,(iii)\,\,Cl\xrightarrow{I.E.}C{{l}^{+}}\,\,\,(iv)\,\,C{{l}^{+}}\xrightarrow{I.E.}Cl^{2+}$

Reason : Crystal field splitting in ferrocyanide ion is greater than that of ferricyanide ion.