MCQ
End product of the reaction sequence is


- A

- B

- C

- ✓$CH_3NH_2$




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Reason : Crystal field splitting in ferrocyanide ion is greater than that of ferricyanide ion.
$ArN _{2} Cl \overset{Cu / HCl}{\rightarrow} ArCl + N _{2}$ is known as
$\mathrm{H}_3 \mathrm{PO}_4 \ \ \ \ \mathrm{H}_2 \mathrm{SO}_4 \ \ \ \ \mathrm{H}_3 \mathrm{PO}_3 \ \ \ \ \mathrm{H}_2 \mathrm{CO}_3 \ \ \ \ \mathrm{H}_2 \mathrm{~S}_2 \mathrm{O}_7 $
$ \mathrm{H}_3 \mathrm{BO}_3 \ \ \ \ \mathrm{H}_3 \mathrm{PO}_2 \ \ \ \ \mathrm{H}_2 \mathrm{CrO}_4 \ \ \ \ \mathrm{H}_2 \mathrm{SO}_3 $
