MCQ
Energy of photon whose frequency is ${10^{12}}MHz,$ will be
- A$4.14 \times {10^3}keV$
- B$4.14 \times {10^2}eV$
- C$4.14 \times {10^3}MeV$
- ✓$4.14 \times {10^3}eV$
✓
Answer
Correct option: D.
$4.14 \times {10^3}eV$
d
(d) $E(eV) = \frac{{h\nu }}{e} = \frac{{6.0 \times {{10}^{ - 34}} \times {{10}^{12}} \times {{10}^6}}}{{1.6 \times {{10}^{ - 19}}}}$$ = 4.14 \times {10^3}eV$.
(d) $E(eV) = \frac{{h\nu }}{e} = \frac{{6.0 \times {{10}^{ - 34}} \times {{10}^{12}} \times {{10}^6}}}{{1.6 \times {{10}^{ - 19}}}}$$ = 4.14 \times {10^3}eV$.
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