MCQ
Energy of the electron in Hydrogen atom is given by
  • A
    ${E_n} = - \frac{{131.38}}{{{n^2}}}\,kJ\,mo{l^{ - 1}}$
  • B
    ${E_n} = - \frac{{131.33}}{n}\,kJ\,mo{l^{ - 1}}$
  • ${E_n} = - \frac{{1313.3}}{{{n^2}}}\,kJ\,mo{l^{ - 1}}$
  • D
    ${E_n} = - \frac{{313.13}}{{{n^2}}}\,kJ\,mo{l^{ - 1}}$

Answer

Correct option: C.
${E_n} = - \frac{{1313.3}}{{{n^2}}}\,kJ\,mo{l^{ - 1}}$
c
It’s Obvious
 

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