MCQ
Energy of the electron in Hydrogen atom is given by
- A${E_n} = - \frac{{131.38}}{{{n^2}}}\,kJ\,mo{l^{ - 1}}$
- B${E_n} = - \frac{{131.33}}{n}\,kJ\,mo{l^{ - 1}}$
- ✓${E_n} = - \frac{{1313.3}}{{{n^2}}}\,kJ\,mo{l^{ - 1}}$
- D${E_n} = - \frac{{313.13}}{{{n^2}}}\,kJ\,mo{l^{ - 1}}$
