$B_{1}=\frac{\mu_{0} I}{2 \pi Q} \hat{J}$
due to wire along $\mathrm{y}$ $-$ axis
$\mathrm{B}_{2}=\frac{\mu_{0} \mathrm{I}}{2 \pi \mathrm{a}}(-\hat{\mathrm{i}})$
due to wire along $\mathrm{Z}$ $-$ axis
${\mathrm{B}_{3}=0} $
${\mathrm{B}_{\mathrm{net}}=\frac{\mu_{0} \mathrm{I}}{2 \pi \mathrm{a}}(\hat{j}-\hat{\mathrm{i}})}$

