Equation of motion in the same direction are given by

${y_1} = 2a\sin (\omega t - kx)$  and  ${y_2} = 2a\sin (\omega t - kx - \theta )$

The amplitude of the medium particle will be

  • A$2a\cos \theta $
  • B$\sqrt 2 a\cos \theta $
  • C$4a\cos \theta /2$
  • D$\sqrt 2 a\cos \theta /2$
Medium
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