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10.1 circle and system of circle — MATHS STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceMATHS10.1 circle and system of circle1 Mark
MCQ
Equation of the circle passing through origin whose centre lie in the first quadrant and length of intercept on $x$ and $y$ -axis is $6$ and $4$ respectively, is
  • A
    $x^2 + y^2 -4x -6y = 0$
  • ✓
    $x^2 + y^2 -6x -4y= 0$
  • C
    $x^2 + y^2 -3x -2y = 0$
  • D
    None of these
✓

Answer

Correct option: B.
$x^2 + y^2 -6x -4y= 0$
b
Given circle is passing through $(0,0),(6,0)(0,4)$ Hence using above formula required circle is $x^{2}+y^{2}-6 x-4 y=0$

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