MCQ
If ${{{x^2}} \over {({x^2} + {a^2})\,({x^2} + {b^2})}} = k\left( {{{{a^2}} \over {{x^2} + {a^2}}} - {{{b^2}} \over {{x^2} + {b^2}}}} \right)$ then $k =$
- A${a^2} - {b^2}$
- B${1 \over {a + b}}$
- C${1 \over {a - b}}$
- ✓${1 \over {{a^2} - {b^2}}}$
$ \Rightarrow $${x^2} = k\,[({a^2} - {b^2}){x^2}] \Rightarrow 1 = k({a^2} - {b^2})$
$\therefore k = {1 \over {{a^2} - {b^2}}}$.
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$x \operatorname{cosec} \alpha-y \sec \alpha=\operatorname{kcot} 2 \alpha$ and $x \sin \alpha+y \cos \alpha=k \sin 2 \alpha$
respectively, then $\mathrm{k}^{2}$ is equal to :