Equipotential surfaces are shown in figure. Then the electric field strength will be

Q: Equipotential surfaces are shown in figure. Then the electric field strength will be

c (c) Using $dV = - \overrightarrow E .d\overrightarrow r $ $⇒$ $\Delta V = - E.\Delta r\cos \theta $ $⇒$ $E = \frac{{ - \Delta V}}{{\Delta r\cos \theta }}$ $⇒$ $E = \frac{{ - (20 - 10)}}{{10 \times {{10}^{ - 2}}\cos 120^\circ }}$ $ = \frac{{ - 10}}{{10 \times {{10}^{ - 2}}( - \sin 30^\circ )}} = \frac{{ - {{10}^2}}}{{ - 1/2}} = 200\,V/m$ Direction of $E$ be perpendicular to the equipotential surface i.e. at $120°$ with $x-$axis.

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

Equipotential surfaces are shown in figure. Then the electric field strength will be

A$100 \,Vm^{-1}$ along $X$-axis
B$100 \,Vm^{-1}$ along $Y$-axis
C$200 \,Vm^{-1}$ at an angle $120°$ with $X$-axis
D$50 \,Vm^{-1}$ at an angle $120°$ with $X$-axis

Diffcult

STD 11 Science
NEET
STD 12 - 2. Electric potential and capacitance
Physics

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