MCQ
Equivalent conductances of $BaCl_2$, $H_2SO_4$ and $HCl$ at infinite dilution are $\Lambda _1^\infty ,\Lambda _2^\infty $ and $\Lambda _3^\infty $ respectively then the equivalent conductance of $BaSO_4$ at infinite dilution will be
- ✓$\Lambda _1^\infty + \Lambda _2^\infty - \Lambda _3^\infty $
- B$\Lambda _1^\infty + \Lambda _2^\infty - 2\Lambda _3^\infty $
- C$\Lambda _1^\infty + \Lambda _2^\infty + \Lambda _3^\infty $
- D$\Lambda _3^\infty - \left( {\Lambda _1^\infty + \Lambda _2^\infty } \right)$
