Answer

Correct option: A.
$3 \Omega$
(a)
$3 \Omega$
Explanation:
$R_1, R_2, R_3$ are in parallel
$
\begin{aligned}
\frac{1}{R^{\prime}} & =\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3} \\
\Rightarrow R^{\prime} & =\frac{1}{3}+\frac{1}{3}+\frac{1}{3} \\
& =1 \Omega
\end{aligned}
$
$R^{\prime}$ and $R_4$ are in series
$
R=R^{\prime}+R_4=1 \Omega+2 \Omega=3 \Omega
$

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