
Hence, the required order is- \(B\, <\, A\, <\, C\).
$(I)$ $ CH_3 - NO_2$
$(II)$ $NO_2 - CH_2 - NO_2$
$(III)$ $ CH_3 - CH_2 - NO_2 $
$(IV)$ $\begin{array}{*{20}{c}}
{N{O_2} - CH - N{O_2}} \\
{|\,\,\,\,\,\,} \\
{\,N{O_2}}
\end{array}$
$(I)$ $C{H_2} = CH\mathop C\limits^ + HC{H_3}$
$\begin{array}{*{20}{c}}
{{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,} \\
{(II)\,\,\,\,\,\,\,\,\,\,C{H_2} = C - \mathop {{\text{ }}C}\limits^ + {H_2}}
\end{array}$
$(III)$ $C{H_3}CH = CH\mathop C\limits^ + {H_2}$


$\mathop {Ph - OH}\limits_{(A)} ,\,\,\,\,\mathop {Ph - C{H_2} - OH}\limits_{(B)} ,\,\,\,\,\mathop {Ph - C{O_2}H}\limits_{(C)} ,\,\,\,\mathop {Ph - C{H_2}-\mathop N\limits^ \oplus {H_3}}\limits_{(D)} $
$(II)\,\,\,{{H}_{2}}C=CH-C{{H}_{2}}-\overset{+}{\mathop{C}}\,H-C{{H}_{3}}$
$(III)\,\,\,\begin{matrix}
\,\,\,\,\,C{{H}_{3}}\, \\
|\, \\
{{H}_{3}}C-C-\overset{+}{\mathop{C}}\,{{H}_{2}} \\
|\, \\
\,\,\,C{{H}_{3}} \\
\end{matrix}$