The repeated enolisation, deutration and dehydration ultimately gives $C{D_3}\,.\,COC{D_3}\,({\rm{B}})$.

$\mathop {C{H_3} - \mathop {\mathop C\limits^{||} }\limits^O  - C{H_3}}\limits_{{\text{Acetone}}\,{\text{(ketoform)}}} $  $\left[ {\mathop {C{H_3} - \mathop {\mathop {C\,\,}\limits^{|\,\,\,\,\,} }\limits^{OH}  = C{H_2}}\limits_{{\text{enol form}}} } \right]$ $\leftrightharpoons $

$C{H_3} - \mathop {\mathop {{\text{ }}C}\limits^|  = }\limits^{OD\,\,\,} C{H_2}$  $\leftrightharpoons $ $C{H_3} - \mathop {\mathop {C{\mkern 1mu} {\mkern 1mu} }\limits^{||{\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} } }\limits^{O\,}  - C{H_2}D$   $\leftrightharpoons $

$C{H_2} = \mathop {\mathop {C{\mkern 1mu} {\mkern 1mu} }\limits^{|{\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} } }\limits^{OH}  = C{H_2}D$ $\overset {{D_2}O} \longleftrightarrow $ $C{H_2} = \mathop {\mathop {C{\mkern 1mu} {\mkern 1mu} }\limits^{|{\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} } }\limits^{OD}  - C{H_2}D$

$DC{H_2} - \mathop {\mathop C\limits^{||} }\limits^O  - C{H_2}D$   $\leftrightharpoons $   ${D_3}C - \mathop {\mathop C\limits^{||} }\limits^O  - C{D_3}$