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8.2 Carboxylic acids and their derivative — Chemistry STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceChemistry8.2 Carboxylic acids and their derivative1 Mark
MCQ
Ethyl acetate reacts with $C{H_3}MgBr$ to form
  • A
    Secondary alcohol
  • ✓
    Tertiary alcohol
  • C
    Primary alcohol and acid
  • D
    Acid
✓

Answer

Correct option: B.
Tertiary alcohol
b
$\underset{Ethyl\,\,acetate}{\mathop{\begin{matrix}
   \,O  \\
   \,||  \\
   C{{H}_{3}}C-C-{{C}_{2}}{{H}_{5}}  \\
\end{matrix}}}$ $+\,C{{H}_{3}}MgBr\,\to $ $\begin{array}{*{20}{c}}
  {\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,\,\,\,O - MgBr} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
\end{array}} \\ 
  {C{H_3} - C - O - {C_2}{H_5}} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3}\,\,\,\,\,\,\,} 
\end{array}$  $\xrightarrow[{ - \,Mg\, < \,\begin{array}{*{20}{c}}
  {Br} \\ 
  {OH} 
\end{array}}]{{ + \,{H_2}O}}$ $\begin{array}{*{20}{c}}
  {\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,OH} \\ 
  | 
\end{array}} \\ 
  {C{H_3} - C - OH} \\ 
  | \\ 
  {\,\,\,\,\,\,\,\,\,C{H_3}} 
\end{array}$ $\xrightarrow{{ - \,{H_2}O}}$ $\begin{array}{*{20}{c}}
  O \\ 
  {||} \\ 
  {C{H_3} - C - C{H_3}} 
\end{array}$ $\xrightarrow[{C{H_3}MgBr}]{{Excess\,\,of}}$ $\begin{array}{*{20}{c}}
  {\begin{array}{*{20}{c}}
  {C{H_3}\,\,} \\ 
  {|\,\,\,\,\,\,\,\,} 
\end{array}} \\ 
  {C{H_3} - C - OMgBr} \\ 
  {\,\,|\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3}\,} 
\end{array}$ $\xrightarrow{{{H_2}O}}$ $\mathop {\begin{array}{*{20}{c}}
  {\begin{array}{*{20}{c}}
  {\,\,\,\,\,C{H_3}} \\ 
  | 
\end{array}} \\ 
  {C{H_3} - C - OH} \\ 
  {\,\,|} \\ 
  {\,\,\,\,\,\,\,\,\,\,C{H_{3.}}} 
\end{array}}\limits_{t\, - \,Butanol} $

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