Ethyl alcohol on heating with conc. H_2 S O_4 gives - Vidyadip

MCQ

Ethyl alcohol on heating with conc. ${H_2}S{O_4}$ gives

A
$C{H_3}COO{C_2}{H_5}$
B
${C_2}{H_6}$
✓
${C_2}{H_4}$
D
${C_2}{H_2}$

✓

Answer

Correct option: C.

${C_2}{H_4}$

c
(c) $C{H_3} - C{H_2} - OH \xrightarrow[H_2SO_4]{Conc.}\mathop {}\limits_{} C{H_2} = C{H_2} + {H_2}O$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 9. Hydricarbon→9. Hydricarbon — all question types→Chemistry STD 11 Science question papers→Rajasthan Board STD 11 Science question papers→Rajasthan Board question paper generator→

Similar questions

For the reaction $2NOBr (g) \rightleftharpoons 2NO(g) + Br_2(g)$, if ${P_{B{r_2}}} = \frac{P}{9}$ at equilibrium and $P$ is total presssure, then find $\frac{{{K_P}}}{P}$ ?

Which one is oxidising substance

How much ....$kJ$ energy is released when $6$ mole of octane is burnt in air ? Given $\Delta H_f^o$ for $C{O_2}(g),\,{H_2}O(g)$ and ${C_8}{H_{18}}(l)$ respectively are $-490,-240\, and + 160 \,kJ/mol$

The concentration of $NaOH$ solution is ${10^{ - 8}}\,M.$ Find out the $(O{H^ - })$ concentration

The ratio of specific charge of a proton and an $\alpha $-particle is

Which of the following shape of molecule is not obtained from the trigonal bipyramidal electronic geometry of the central atom ?

The enthalpies of combustion of $S(s)$ and $H_2(g)$ are $ -300$ and $-290\,\, kcal\,\, mol^{-1.}$

Given $SO_3(g) + H_2O(l) \rightarrow H_2SO_4(l)$
$\Delta H = -130\,\, kcal\, mol^{-1}$
$SO_2(g) + 1/2O_2(g) \rightarrow SO_3(g)$
$\Delta H = -100 \,\,kcal\,\, mol^{-1}$
the enthalpy of formation of $H_2SO_4(l)$ would be ......$kcal\, mol^{-1}$

Caffeine has a molecular weight of $194$. If it contains $28.9\%$ by mass of nitrogen, number of atoms of nitrogen in one molecule of caffeine is

Assertion : Boron is metalloid.

Reason : Boron shows metallic nature.

The lattice energies of $KF, KCl, KBr$ and $KI$ follow the order