MCQ
Ethyl nitrite on reduction with Sn/ HCI gives:
  • A
    C2​H5​NH​+ HNO2
  • B
    C2​H5​NH2​ + H2​O
  • C
    C2​H5​OH + NH4​OH
  • D
    C2​H5​OH + NaNO2

Answer

  1. C2​H5​OH + NH4​OH

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