Ethyl nitrite on reduction with Sn/ HCI gives: - Vidyadip

MCQ

Ethyl nitrite on reduction with $\text{Sn/ HCI}$ gives:

A
$ \mathrm{C}_2 \mathrm{H}_5 \mathrm{NH}_2+\mathrm{HNO}_2 $
B
$ \mathrm{C}_2 \mathrm{H}_5 \mathrm{NH}_2+\mathrm{H}_2 \mathrm{O} $
✓
$ \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}+\mathrm{NH}_4 \mathrm{OH} $
D
$ \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}+\mathrm{NaNO}_2 $

✓

Answer

Correct option: C.

$ \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}+\mathrm{NH}_4 \mathrm{OH} $

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