- AOxalic acid
- BGlycol
- ✓Formaldehyde
- DGlycollic acid
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$(C-H= 414; H-O = 463; H-Cl=431;$$ C-Cl=326, C-O=335)$
$CH_3-OH(g) + HCl(g) \rightarrow CH_3-Cl(g) + H_2O(g)$
$NO(g) \rightarrow \frac{1}{2} N_2(g)+ \frac{1}{2} O_2(g)$ at the same temperature is :
| $Pb ^{2+} / Pb$ | $-0.13 V$ |
| $Ni ^{2+} / Ni$ | $-0.24 V$ |
| $Cd ^{2+} / Cd$ | $-0.40 V$ |
| $Fe ^{2+} / Fe$ | $V-0.44 V$ |
To a solution containing $0.001 M$ of $X ^{2+}$ and $0.1 M$ of $Y ^{2+}$, the metal rods $X$ and $Y$ are inserted (at $298 K$ ) and connected by a conducting wire. This resulted in dissolution of $X$. The correct combination(s) of $X$ and $Y$, respectively, is (are)
(Given: Gas constant, $R =8.314 J K ^{-1} mol ^{-1}$,
Faraday constant, $F =96500 C mol ^{-1}$ )
$(A)$ $Cd$ and $Ni$ $(B)$ $Cd$ and $Fe$ $(C)$ $Ni$ and $Pb$ $(D)$ $Ni$ and $Fe$
$(i)$ $N{O_2}\xrightarrow{{slow}}NO + O$
$(ii)$ ${F_2} + O + NO\xrightarrow{{Fast}}N{O_2}F + F$
$(iii)$ $F + N{O_2}\xrightarrow{{Fast}}N{O_2}F$
Select the correct one