Evaluate: -1+2 -3 +5 6 - Vidyadip

Question

Evaluate: $-1+\frac{2}{-3}+\frac{5}{6}$

✓

Answer

$-1+\frac{2}{-3}+\frac{5}{6}$

2	3,6
3	3,3
	1,1

L.C.M. of 3 and $6=2 \times 3=6$
$ \begin{aligned} & \Rightarrow \frac{-1 \times 6}{1 \times 6}-\frac{2 \times 2}{3 \times 2}+\frac{5 \times 1}{6 \times 1} \\ & (\because \text { L.C.M. of } 3 \text { and } 6=6) \end{aligned} $
$ \Rightarrow \frac{-6-4+5}{6} $
$ =\frac{-10+5}{6}=-\frac{5}{6} $

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "[5 marks sum]" from Rational Numbers→Rational Numbers — all question types→MATHS STD 7 question papers→ICSE Board STD 7 question papers→ICSE Board question paper generator→

Similar questions

Find the mean, the median, and the mode of 12, 24, 24, 12, 30 and 12.

40 pens are bought at 4 for Rs. 50 and all of them are sold at 5 for Rs. 80 Find
(i) C.P. of one pen.
(ii) S/P. of one pen.
(iii) Profit made by selling one pen.
(iv) Profit percent made by selling one pen.
(v) C.P. of 40 pens
(vi) S.P. of 40 pens.
(vii) Profit made by selling 40 pens.
(viii) Profit percent made by selling 40 pens. Are the results of parts (iv) and (viii) same? What conclusion do you draw from the above result?

Construct a ∆ PQR such that PQ = 6 cm, ∠QPR = 45° and angle PQR = 60°. Locate its incentre and then draw its incircle.

Draw a line segment AB = 5.8 cm. Mark a point P in AB such that PB = 3.6 cm. At P, draw a perpendicular to AB.

Arrange the given fraction in descending order by making numerator equal:
$\frac{1}{10}, \frac{6}{11}, \frac{8}{11} \text { and } \frac{3}{5}$

The length of a rectangular plot exceeds its breadth by 5 m. If the perimeter of the plot is 142 m, find the length and the breadth of the plot.

Using ruler and compasses, construct the following angle:
165°

From a sack of potatoes weighing $120 \mathrm{~kg}$, a merchant sells portions weighing $6 \mathrm{~kg}, 5 \frac{1}{4} \mathrm{~kg}, 9 \frac{1}{2} \mathrm{~kg}$, and $9 \frac{3}{4} \mathrm{~kg}$ respectively.
(i) How many kg did he sell?
(ii) How many kg is still left in the sack?

In the given figure, BI is the bisector of ∠ABC and Cl is the bisector of ∠ACB. Find ∠BIC.

A vendor bought 120 sweets at 20 p each. In his house, 18 were consumed and he sold the remaining at 30 p each. Find his profit or loss as percent.