Question
Using ruler and compasses, construct the following angle:
165°
165°
✓
Answer
Steps of Construction:
(i) Draw a line segment $B C$.
(ii) With centre $B$ and some suitable radius draw an arc meeting $B C$ at $P$.
(iii) With centre $P$ and same radius cut off arcs $P Q, Q R$ and then RS.
(iv) Join SB.
(v) With centres R and S, draw two arcs intersecting each other at M.
(vi) With centre $T$ and $S$ draw two arcs intersecting each other at L.
(vii) Join BL and produce it to $A$. Then $\angle A B C=165^{\circ}$
(i) Draw a line segment $B C$.
(ii) With centre $B$ and some suitable radius draw an arc meeting $B C$ at $P$.
(iii) With centre $P$ and same radius cut off arcs $P Q, Q R$ and then RS.
(iv) Join SB.
(v) With centres R and S, draw two arcs intersecting each other at M.
(vi) With centre $T$ and $S$ draw two arcs intersecting each other at L.
(vii) Join BL and produce it to $A$. Then $\angle A B C=165^{\circ}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Using ruler and compasses, construct the following angle:
37.5°
37.5°
Put the given fraction in ascending order by making denominator equal:
$\frac{5}{6}, \frac{7}{8}, \frac{11}{12} \text { and } \frac{3}{10}$
→$\frac{5}{6}, \frac{7}{8}, \frac{11}{12} \text { and } \frac{3}{10}$
Evaluate:
(i) $(a+b)(a-b)$
(ii) $\left(a^2+b^2\right)(a+b)(a-b)$; using the result of (i).
(iii) $\left(a^4+b^4\right)\left(a^2+b^2\right)(a+b)(a-b)$; using the result of (ii).
→(i) $(a+b)(a-b)$
(ii) $\left(a^2+b^2\right)(a+b)(a-b)$; using the result of (i).
(iii) $\left(a^4+b^4\right)\left(a^2+b^2\right)(a+b)(a-b)$; using the result of (ii).
Evaluate: $\frac{-5}{9}+\frac{-7}{12}+\frac{11}{18}$
→Construct an equilateral triangle ABC such that it's one side = 5.5 cm. Construct a circumcircle to this triangle.
Arrange the given fraction in descending order by making numerator equal:
$\frac{1}{10}, \frac{6}{11}, \frac{8}{11} \text { and } \frac{3}{5}$
→$\frac{1}{10}, \frac{6}{11}, \frac{8}{11} \text { and } \frac{3}{5}$
In the given figure, angle $A C B=90^{\circ}=$ angle $A C D$. If $A B=10 m , B C$ $=6 cm$ and $A D=17 cm$, find :
(i) $AC$
(ii) $CD$
→(i) $AC$
(ii) $CD$
Put the given fraction in ascending order by making denominator equal:
$\frac{5}{7}, \frac{3}{8}, \frac{9}{14} \text { and } \frac{20}{21}$
→$\frac{5}{7}, \frac{3}{8}, \frac{9}{14} \text { and } \frac{20}{21}$
The difference between two numbers is 7. Six times the smaller plus the larger is 77. Find the numbers.
The adjacent sides of a parallelogram are 15 cm and 10 cm. If the distance between the longer sides is 6 cm, find the distance between the shorter sides.