Question
Evaluate : $(3−2x) (3+2x) (9+4x^2)$

Answer

$(3−2x) (3+2x) (9+4x^2)$
$= [{3}^2−(2x)^2] (9+4x^2)$
$= (9−4x^2) (9+4x^2)$
$= (9)^2 − (4x^2)^2$
$= 81 − 16x^4$

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