Find the cube of: x-1 2 - Vidyadip

Question

Find the cube of: $x-\frac{1}{2}$

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Answer

$ \left(\mathrm{x}-\frac{1}{2}\right)^3$
$ =(\mathrm{x})^3-\left(\frac{1}{2}\right)^3-3 \times \mathrm{x} \times \frac{1}{2}\left(\mathrm{x}-\frac{1}{2}\right)$
$ =\mathrm{x}^3-\frac{1}{8}-\frac{3 \mathrm{x}}{2}\left(\mathrm{x}-\frac{1}{2}\right)$
$ =\mathrm{x}^3-\frac{1}{8}-\frac{3 \mathrm{x}^2}{2}+\frac{3 \mathrm{x}}{4}$
$ =\mathrm{x}^3-\frac{3 \mathrm{x}^2}{2}+\frac{3 \mathrm{x}}{4}-\frac{1}{8}$

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