Question
Evaluate:
$48^3-30^3-18^3$
$48^3-30^3-18^3$
✓
Answer
Let $\mathrm{a}=48, \mathrm{~b}=-30$ and $\mathrm{c}=-18$
Then,
$a+b+c=48-30-18$
$=0$
$\therefore a^3+b^3+c^3=3 a b c$
$\Rightarrow(48)^3+(-30)^3+(-18)^3=3 \times(48) \times(-30) \times(-18)$
$=144 \times 540$
$=77760$
$\therefore 48^3-30^3-18^3=77760$
Then,
$a+b+c=48-30-18$
$=0$
$\therefore a^3+b^3+c^3=3 a b c$
$\Rightarrow(48)^3+(-30)^3+(-18)^3=3 \times(48) \times(-30) \times(-18)$
$=144 \times 540$
$=77760$
$\therefore 48^3-30^3-18^3=77760$
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