Question
Evaluate: $\frac{4}{9}-\frac{2}{-3}$
✓
Answer
$\frac{4}{9}-\frac{2}{-3}$ $LCM$ of $9$ and $3 = 9$
$\therefore\frac{2}{-3}=\frac{2\times(-1)}{-3\times(-1)}=\frac{-2}{3}$
$=\frac{-2\times3}{3\times3}=\frac{-6}{9}$
$\therefore\frac{4}{9}-\frac{2}{-3}=\frac{4}{9}-\Big(\frac{-6}{9}\Big)$
$=\frac{4}{9}+\frac{6}{9}$ $=\frac{4+6}{9}$
$=\frac{10}{9}$
$\therefore\frac{2}{-3}=\frac{2\times(-1)}{-3\times(-1)}=\frac{-2}{3}$
$=\frac{-2\times3}{3\times3}=\frac{-6}{9}$
$\therefore\frac{4}{9}-\frac{2}{-3}=\frac{4}{9}-\Big(\frac{-6}{9}\Big)$
$=\frac{4}{9}+\frac{6}{9}$ $=\frac{4+6}{9}$
$=\frac{10}{9}$
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