Question
Solve the following equations by trial and error method.
$3 m-14=4$
$3 m-14=4$
✓
Answer
Given equation is $3 m-14=4$.
When $m=0$, then LHS $=3 \times 0-14=0-14=-14$
and$\qquad$RHS $=4$
$\therefore $ LHS $\neq$ RHS
$\begin{array}{l}\text { When } m=1 \text {, then } \\ \text { LHS }=3 \times 1-14=3-14=-11 \\ \text { and }\quad \text { RHS }=4 \\ \therefore \text { LHS } \neq \text { RHS }\end{array}$
When $m=2$, then
LHS $=3 \times 2-14=6-14=-8$
and RHS $=4
\Rightarrow$ LHS $\neq$ RHS
When $m=3$, then
LHS $=3 \times 3-14=9-14=-5$
and RHS $=4
\Rightarrow$ LHS $\neq$ RHS
When $m=4$, then
LHS $=3 \times 4-14=12-14=-2$
and RHS $=4 \Rightarrow$ LHS $\neq$ RHS
When $m=5$, then
LHS $=3 \times 5-14=15-14=1$
and RHS $=4
\Rightarrow \quad$ LHS $\neq$ RHS
When $m=6$, then
LHS $=3 \times 6-14=18-14$
and RHS $=4
\Rightarrow \quad$ LHS $=$ RHS
Hence, $m=6$ is the solution of the given equation.
When $m=0$, then LHS $=3 \times 0-14=0-14=-14$
and$\qquad$RHS $=4$
$\therefore $ LHS $\neq$ RHS
$\begin{array}{l}\text { When } m=1 \text {, then } \\ \text { LHS }=3 \times 1-14=3-14=-11 \\ \text { and }\quad \text { RHS }=4 \\ \therefore \text { LHS } \neq \text { RHS }\end{array}$
When $m=2$, then
LHS $=3 \times 2-14=6-14=-8$
and RHS $=4
\Rightarrow$ LHS $\neq$ RHS
When $m=3$, then
LHS $=3 \times 3-14=9-14=-5$
and RHS $=4
\Rightarrow$ LHS $\neq$ RHS
When $m=4$, then
LHS $=3 \times 4-14=12-14=-2$
and RHS $=4 \Rightarrow$ LHS $\neq$ RHS
When $m=5$, then
LHS $=3 \times 5-14=15-14=1$
and RHS $=4
\Rightarrow \quad$ LHS $\neq$ RHS
When $m=6$, then
LHS $=3 \times 6-14=18-14$
and RHS $=4
\Rightarrow \quad$ LHS $=$ RHS
Hence, $m=6$ is the solution of the given equation.
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