Question
Evaluate $\left(-8 x^2 y^5\right) \times(-20 x y)$ for $x=2.5$ and $y=1$

Answer


To multiply algebraic expressions, we use commutative and associative laws along with the law of indices, i.e. $a ^{ m } \times a ^{ n }$ $=a^{m+n}$.
We have:
$\left(-8 x^2 y^6\right) \times(-20 x y)$
$=[(-8) \times(-20)] \times\left(x^2 \times x\right) \times\left(y^6 \times y\right)$
$=[(-8) \times(-20)] \times\left(x^2+1\right) \times\left(y^6+1\right)$
$=160 x^3 y^7$
$\left(-8 x^2 y^6\right) \times(-20 x y)=160 x^3 y^7$
Substituting $x=2.5$ and $y=1$ in the result, we get:
$=160 x^3 y^7$
$=160(2.5)^3(1)^7$
$=160 \times 15.625$
$=2500$
Thus, the answer is 2500 .

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