Evaluate $\begin{bmatrix}1&0&1\\0&0&1\\1&0&1\end{bmatrix}$ is:
- 2
- 0
- 1
- -1
Evaluate $\begin{bmatrix}1&0&1\\0&0&1\\1&0&1\end{bmatrix}$ is:
Solution:
$\triangle=\begin{bmatrix}1&0&1\\0&0&1\\1&0&1\end{bmatrix}$
$\triangle=1\begin{bmatrix}0&1\\0&1\end{bmatrix}-0\begin{bmatrix}0&1\\1&1\end{bmatrix}+1\begin{bmatrix}0&0\\1&0\end{bmatrix}$
$\triangle=1(0-0)-0(0-1)+1(0-0)$
$\triangle=0-0+0=0.$
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Solution of the differential equation $\frac{\text{dy}}{\text{dx}}+\frac{\text{y}}{\text{x}}=\sin\text{x}$ is:
$\text{x}(\text{y}+\cos\text{x})=\sin\text{x}+\text{c}$
$\text{x}(\text{y}-\cos\text{x})=\sin\text{x}+\text{c}$
$\text{x}\text{y}\cos\text{x}=\sin\text{x}+\text{c}$
$\text{x}(\text{y}+\cos\text{x})=\cos\text{x}+\text{c}$