Question
Evaluate $\Big(\frac{81}{49}\Big)^{\frac{-3}{2}}.$

Answer

$\Big(\frac{81}{49}\Big)^{\frac{-3}{2}}$ $=\Big(\frac{49}{81}\Big)^{\frac{3}{2}}$ $=\Big(\frac{7^2}{9^2}\Big)^{\frac{3}{2}}$ $=\Big(\frac{7}{9}\Big)^{2\times\frac{3}{2}}$ $=\Big(\frac{7}{9}\Big)^3$ $=\frac{343}{729}$

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