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Exponents — Maths STD 8 — Question

Maharashtra BoardEnglish MediumSTD 8MathsExponents2 Marks
Question
Evaluate $\Big[\big(5^{-1}\times3^{-1}\big)\div6^{-1}\Big]$
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Answer

$\Big[\big(5^{-1}\times3^{-1}\big)\div6^{-1}\Big]$$=\Big(\frac{1}{5}\times\frac{1}{3}\Big)^{-1}\div\frac{1}{6}$
$=\Big(\frac{1}{15}\Big)^{-1}\div\frac{1}{6}$
$=(15)^1\div\frac{1}{6}$ $=15\times\frac{6}{1}$ $=90$

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