Question
Evaluate:
$\Big(\frac{2}{3}\Big)^{-3}\times\Big(\frac{2}{3}\Big)^{-2}$

Answer

$\Big(\frac{2}{3}\Big)^{-3}\times\Big(\frac{2}{3}\Big)^{-2}$
$=\Big(\frac{3}{2}\Big)^{3}\times\Big(\frac{3}{2}\Big)^{2}$
$=\Big(\frac{3}{2}\Big)^{3+2}$
$=\Big(\frac{3}{2}\Big)^{5}$
$=\frac{3}{2}\times\frac{3}{2}\times\frac{3}{2}\times\frac{3}{2}\times\frac{3}{2}$
$=\frac{243}{32}$

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