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Exponents — Maths STD 8 — Question

Maharashtra BoardEnglish MediumSTD 8MathsExponents2 Marks
Question
Evaluate:
$\Bigg\{\Big(\frac{4}{3}\Big)^{-1}-\Big(\frac{1}{4}\Big)^{-1}\Bigg\}^{-1}$
✓

Answer

$\Bigg\{\Big(\frac{4}{3}\Big)^{-1}-\Big(\frac{1}{4}\Big)^{-1}\Bigg\}^{-1}$$=\Bigg\{\Big(\frac{3}{4}\Big)^{1}-\Big(\frac{4}{1}\Big)^{1}\Bigg\}^{-1}$
$=\Big(\frac{3}{4}-\frac{4}{1}\Big)^{-1}$
$=\Big(\frac{3-16}{4}\Big)^{-1}$
$=\Big(\frac{-13}{4}\Big)^{-1}$
$=\frac{-4}{13}$

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