Question
Fill in blanks:$\frac{-7}{9}+ \ ........ \ =3$

Answer

$\frac{-7}{9}+\frac{34}{9} =3$Solution:
Required number $=3-\Big(\frac{-7}{9}\Big)$ $=\frac{3}{1}+\frac{7}{9}$ $=\frac{27+7}{9}$ $=\frac{34}{9}$

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