Evaluate : _ x 2 x^2-4 x+3 : - Vidyadip

MCQ

Evaluate : $\displaystyle\lim_{\text{x}\rightarrow 2} \dfrac{\text{x}^2-4}{\text{x}+3}:$

✓
$0$
B
$1$
C
$-1$
D
None of these

✓

Answer

Correct option: A.

$0$

Using direct substitution, we obtain,$ =\displaystyle\lim_{\text{x}\rightarrow 2} \dfrac{\text{x}^2-4}{\text{x}+3}$
$ =\dfrac{4-4}{2+3}$
$=0$

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