Question
Evaluate: $\frac{-45}{39} \times \frac{-13}{15}$

Answer


$\begin{aligned} & \frac{-45}{39} \times \frac{-13}{15} \\ & =\frac{(-45) \times(-13)}{39 \times 15}=\frac{(-3) \times(-1)}{3 \times 1} \\ & =\frac{3}{3}=1\end{aligned}$

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