Question
Evaluate: $\frac{-9}{4}+\frac{13}{3}+\frac{25}{6}$
✓
Answer
$\frac{-9}{4}+\frac{13}{3}+\frac{25}{6}$
LCM of $4,3$ and $6$ is $12 .$
$ \frac{-9}{4} \Rightarrow \frac{-9}{4} \times \frac{3}{3}=\frac{-27}{12}$
$\frac{13}{3} \Rightarrow \frac{13}{3} \times \frac{4}{4}=\frac{52}{12}$
$\frac{25}{6} \Rightarrow \frac{25}{6} \times \frac{2}{2}=\frac{50}{12}$
$=\frac{-27+52+50}{12} $
$=\frac{75}{12}=\frac{25}{4}$
$\therefore \frac{-9}{4}+\frac{13}{3}+\frac{25}{6}=\frac{25}{4}$
LCM of $4,3$ and $6$ is $12 .$
$ \frac{-9}{4} \Rightarrow \frac{-9}{4} \times \frac{3}{3}=\frac{-27}{12}$
$\frac{13}{3} \Rightarrow \frac{13}{3} \times \frac{4}{4}=\frac{52}{12}$
$\frac{25}{6} \Rightarrow \frac{25}{6} \times \frac{2}{2}=\frac{50}{12}$
$=\frac{-27+52+50}{12} $
$=\frac{75}{12}=\frac{25}{4}$
$\therefore \frac{-9}{4}+\frac{13}{3}+\frac{25}{6}=\frac{25}{4}$
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