Download App

Rational Numbers — MATHS STD 7 — Question

ICSE BoardEnglish MediumSTD 7MATHSRational Numbers5 Marks
Question
Evaluate: $\frac{7}{-27}+\frac{11}{18}$
✓

Answer

$\frac{7}{-27}+\frac{11}{18}$
227,18
327,9
39,3
33,1
1,1

L.C.M. of 27 and $18=2 \times 3 \times 3 \times 3=54$
$ \begin{aligned} & \Rightarrow \frac{7 \times 2}{-27 \times 2}+\frac{11 \times 3}{18 \times 3} \\ & (\because \text { L.C.M. of }-27 \text { and } 18=54) \\ & \Rightarrow \frac{-14+33}{54}=\frac{19}{54} \mathrm{} \end{aligned} $

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "[5 marks sum]" from Rational Numbers→Rational Numbers — all question types→MATHS STD 7 question papers→ICSE Board STD 7 question papers→ICSE Board question paper generator→

Similar questions

Evaluate: $-\frac{5}{7}-\left(-\frac{3}{8}\right)$
→
A bag contains ₹ 1,600 in the form of ₹ 10 and ₹ 20 notes. If the ratio between the numbers of ₹ 10 and ₹ 20 notes is 2 : 3; find the total number of notes in all.
→
Evaluate: $\left(\frac{7}{8} \times \frac{24}{21}\right)+\left(\frac{-5}{9} \times \frac{6}{-25}\right)$
→
A shopkeeper buys an article for ₹ 300. He increases its price by 20% and then gives 10% discount on the new price. Find:
(i) the new price (marked price) of the article.
(ii) the discount is given by the shopkeeper.
(iii) the selling price.
(iv) profit percent made by the shopkeeper.
→
The ratio between the areas of two circles is 16 : 9. Find the ratio between their :
(i) radius
(ii) diameters
(iii) circumference
→
A square lawn is surrounded by a path 2.5 m wide. If the area of the path is $165 m^2$ find the area of the lawn.
→
Evaluate: $\left[\left(\frac{5}{6}\right)^2 \times \frac{9}{4}\right] \div\left[\left(-\frac{3^2}{2}\right) \times \frac{125}{216}\right]$
→
The difference between two numbers is 7. Six times the smaller plus the larger is 77. Find the numbers.
→
Construct a ∆ ABC such that AB = 6 cm, BC = 5.6 cm and CA = 6.5 cm.
Inscribe a circle to this triangle and measure its radius.
→
Evaluate: $\left(\frac{-4}{5} \times \frac{3}{2}\right)+\left(\frac{9}{-5} \times \frac{10}{3}\right)-\left(\frac{-3}{2} \times \frac{-1}{4}\right)$
→