Evaluate: 1 x+3 x d x - Vidyadip

MCQ

Evaluate: $\int \frac{1}{\sin x+\sqrt{3} \cos x} d x$

✓
$\frac{1}{2} \log \left|\tan \left(\frac{x}{2}+\frac{\pi}{6}\right)\right|+C$
B
$\frac{1}{2} \log \left|\tan \frac{x}{2}\right|+C$
C
$\frac{1}{2} \log \left|\tan \left(\frac{x}{2}-\frac{\pi}{6}\right)\right|+C$
D
$\frac{1}{2} \log \left|\tan \left(x-\frac{\pi}{6}\right)\right|+C$

✓

Answer

Correct option: A.

$\frac{1}{2} \log \left|\tan \left(\frac{x}{2}+\frac{\pi}{6}\right)\right|+C$

(a) : Let $I=\int \frac{1}{\sin x+\sqrt{3} \cos x} d x$
$
\begin{array}{l}
=\frac{1}{2} \int \frac{d x}{\frac{1}{2} \sin x+\frac{\sqrt{3}}{2} \cos x} \\
\Rightarrow \quad I=\frac{1}{2} \int \frac{1}{\sin \left(x+\frac{\pi}{3}\right)} d x=\frac{1}{2} \int \operatorname{cosec}\left(x+\frac{\pi}{3}\right) d x \\
\Rightarrow \quad I=\frac{1}{2} \log \left|\tan \left(\frac{x}{2}+\frac{\pi}{6}\right)\right|+C \\
{\left[\because \int \operatorname{cosec} x d x=\log \left|\tan \frac{x}{2}\right|+C\right]} \\
\end{array}
$

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