MCQ
If $a=\sin ^{-1}(\sin (5))$ and $b=\cos ^{-1}(\cos (5))$, then $a^2+b^2$ is equal to
- A$4 \pi^2+25$
- ✓$8 \pi^2-40 \pi+50$
- C$4 \pi^2-20 \pi+50$
- D$25$
$\text { and } b=\cos ^{-1}(\cos 5)=2 \pi-5 $
$\therefore a^2+b^2=(5-2 \pi)^2+(2 \pi-5)^2 $
$=8 \pi^2-40 \pi+50$
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In a binomial distribution, the probability of getting success is $\frac{1}{4}$ and standard deviation is 3. Then, its mean is:
$R=\left\{(x, y): \max \left\{0, \log _{e} x\right\} \leq y \leq 2^{x}, \frac{1}{2} \leq x \leq 2\right\}$
is, $\alpha\left(\log _{e} 2\right)^{-1}+\beta\left(\log _{e} 2\right)+\gamma$, then the value of $(\alpha+\beta-2 \gamma)^{2}$ is equal to:
$g(3 n+1)=3 n+2$
$g(3 n+2)=3 n+3$
$g(3 n+3)=3 n+1, \text { for all } n \geq 0$
Then which of the following statements is true?