Question
Evaluate: $\int \frac{1}{x \log x \log (\log x)} d x$
Let $I=\int \frac{1}{x \cdot \log x \log (\log x)} d x$
Put log (log x) = t
Differentiating w.r.t. x, we get
$\frac{1}{\log x} \frac{.1}{x} d x=d t$
$I=\int \frac{1}{t} d t=\log |t|+c$
$I=\log |\log (\log x)|+c$
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