Question
Evaluate: $\int \sec ^n x \tan x d x$

Answer

$I=\int \sec ^{n-1} x \sec x \tan x d x$
Let secx=t
$\begin{aligned} & \therefore \sec x \tan x d x=d t \\ & I=\int t^{n-1} d t \\ & =\frac{t^n}{n}+c \\ & =\frac{\sec ^n x}{n}+C\end{aligned}$

 

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