Question
Using truth table verify that : $(p \wedge q) \vee \sim q \equiv p \vee \sim q$
| $p$ | $q$ | $\sim q$ | $(p \wedge q)$ | $(p \wedge q) \vee \sim q$ | $p \vee \sim q$ |
| 1 | 2 | 3 | 4 | 5 | 6 |
| T | T | F | T | T | T |
| T | F | T | F | T | T |
| F | T | F | F | F | F |
| F | F | T | F | T | T |
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$5 \hat{i}+4 \hat{j}+3 \hat{k}$ and having direction ratios $-3,4,2$.