Question
Evaluate: $\int_0^{\frac{\pi}{4}} \sec ^2 x d x$

Answer

$\int_0^{\frac{\pi}{4}} \sec ^2 x d x=[\tan x]_0^{\frac{\pi}{4}}$
$=\tan \frac{\pi}{4}-\tan 0$
$=1-0$
$=1$

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