Question
Evaluate $\int\sec^2(7-4\text{x})\text{dx}$

Answer

$\int\sec^2(7-4\text{x})\text{dx}$
$=\frac{\tan(7-4\text{x})}{-4}+\text{C}$ $(\because\sec^2\text{x}=\tan\text{x}+\text{C})$

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