Question
Evaluate $\lim _{x \rightarrow 0}\left(e^x-1\right).$

Answer


$\begin{array}{l}\lim _{x \rightarrow 0}\left(e^x-1\right) \\ \lim _{x \rightarrow 0}\left[1+x+\frac{x^2}{\lfloor 2}+\ldots \ldots-1\right]=\lim _{x \rightarrow 0}\left(x+\frac{x^2}{\lfloor{2}}+\ldots \ldots .\right)=0\end{array}$

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