Question 11 Mark
Evaluate $\lim _{x \rightarrow 0}\left(e^x-1\right).$
Answer
$\begin{array}{l}\lim _{x \rightarrow 0}\left(e^x-1\right) \\ \lim _{x \rightarrow 0}\left[1+x+\frac{x^2}{\lfloor 2}+\ldots \ldots-1\right]=\lim _{x \rightarrow 0}\left(x+\frac{x^2}{\lfloor{2}}+\ldots \ldots .\right)=0\end{array}$
View full question & answer→$\begin{array}{l}\lim _{x \rightarrow 0}\left(e^x-1\right) \\ \lim _{x \rightarrow 0}\left[1+x+\frac{x^2}{\lfloor 2}+\ldots \ldots-1\right]=\lim _{x \rightarrow 0}\left(x+\frac{x^2}{\lfloor{2}}+\ldots \ldots .\right)=0\end{array}$