Evaluate : cosec^ -1 (2 / 3) - Vidyadip

Question

Evaluate : $\operatorname{cosec}^{-1}(2 / \sqrt{3})$

✓

Answer

(b) : $\operatorname{cosec}^{-1}(2 / \sqrt{3})=\operatorname{cosec}^{-1}\left(\operatorname{cosec}\left(\frac{\pi}{3}\right)\right)=\frac{\pi}{3}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Inverse Trigonometric Functions→Inverse Trigonometric Functions — all question types→MATHS STD 12 Science question papers→Rajasthan Board STD 12 Science question papers→Rajasthan Board question paper generator→

Similar questions

$\int\frac{\text{dx}}{\sqrt{\text{x}}}=$

$\sqrt{\text{x}}+\text{k}$
$2\sqrt{\text{x}}+\text{k}$
$\text{x}+\text{k}$
$\frac{2}{3}\times\frac{3}{2}+\text{k}$

The vector equation of the line passing through the point (-1, 5, 4) and perpendicular to the plane z = 0 is:

If $f : R \rightarrow R$ and $g : R \rightarrow R$ defined by $f(x) = 2x + 3$ and $g(x) = x^2 + 7,$ then the value of $x$ for which $f(g(x)) = 25$ is:

Let $\text{f(x)}=\frac{\tan\Big(\frac{\pi}{4}-\text{x}\Big)}{\cot2\text{x}},\text{ x}\neq\frac{\pi}{4}$ The value which should be assigned to f(x) at $\text{x}=\frac{\pi}{4},$ so that it is continuous everywhere is:

1
$\frac{1}{2}$
2
None of these.

If $y=\tan ^{-1}\left(e^{2 x}\right)$, then $\frac{d y}{d x}$ is equal to

If $\vec{\text{a}}$ and $\vec{\text{b}}$ be two unit vectors and $\theta$ the angle between them, than $\vec{\text{a}}+\vec{\text{b}}$ is a unit vector if $\theta=$

$\frac{\pi}{4}$
$\frac{\pi}{3}$
$\frac{\pi}{2}$
$\frac{2\pi}{3}$

A bag contains 12 balls out of which x are white. If one ball is drawn at random, what is the probability it will be a white ball?

ox, oy are positive x-axis, positive y-axis respectively where O = (0, 0,0) The d.c.s of the llne which bisects $\angle\text{xoy}$ are:

The position vectors of P and Q are respectively a and b.If R is a point on PQ, PQ such that PR = 5PQ, then the position vector of R is:

5b − 4a
5b + 4a
4b − 5a
4b + 5a

Let * be a binary operation defined on set Q − {1} by the rule a * b = a + b − ab. Then, the identify element for * is:

$1$
$\frac{\text{a}-1}{\text{a}}$
$\frac{\text{a}}{\text{a}-1}$
$0$