Question
Evaluate: $\sqrt[3]{-216}$
✓
Answer
We know that $\sqrt[3]{-216}=-\sqrt[3]{216}$
Resolving $216$ into prime factors,
We get, $216= \underline{2\times2\times 2}\times\underline{3\times3\times3}$
$= (2\times 3)^3$
$=(6)^3$
$\therefore\sqrt[3]{216}=6 $
$\therefore\sqrt[3]{-216}=-(\sqrt[3]{216})=-6 $
Resolving $216$ into prime factors,
We get, $216= \underline{2\times2\times 2}\times\underline{3\times3\times3}$
$= (2\times 3)^3$
$=(6)^3$
$\therefore\sqrt[3]{216}=6 $
$\therefore\sqrt[3]{-216}=-(\sqrt[3]{216})=-6 $
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