Question
Factorise the following, using the identity $a^2- 2ab + b^2= (a - b)^2$.
$x^2- 8x + 16$
$x^2- 8x + 16$
✓
Answer
$ x^2-8 x+16 $
$ =x^2-2 \times x \times 4+4^2 $
$ =(x-4)^2 $
$ =(x-4)(x-4) $
$ =x^2-2 \times x \times 4+4^2 $
$ =(x-4)^2 $
$ =(x-4)(x-4) $
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